第1回小問模試・第9問 答え

$$\begin{align}& (-2x^2)^3 \div A \div (3x^2)^2 = -2\\&-8x^6 \times \frac{1}{A} \times \frac{1}{9x^4} = -2\\A &= -8x^6 \times \frac{1}{9x^4} \times \left(-\frac{1}{2}\right)\\&=\frac{8x^6}{9x^4 \times 2}\\&=\frac{4 x^2}{9}\end{align}$$